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Q.

A capacitor of capacitance C is initially charged to a potential difference of V volt. Now it is connected to a battery of 2V with opposite polarity. The ratio of heat generated to the final energy stored in the capacitor will be n/4 where ‘n’ is

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answer is 11.

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Detailed Solution

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⇒ΔU=12C(2V)2−V2=32CV2WB=2V[2CV−(−CV)]=6CV2

Heat generated =6CV2-1.5CV2=4.5CV2

ratio=Heat generatedFinal energy stored=4.5CV22CV2=2.25 

n4=2.25⇒n=11

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