A capacitor of capacitance C₁ = C is charged to a voltage V . It is then connected in parallel with a series combination of two uncharged capacitors of capacitances C₂ = C and C₃ = C. The charge that will flow through the connecting wires is

Charge on $C_1$ is $Q_1=C_{1}V=CV$. This charge is shared by the three capacitors. 

The equivalent capacitance of the series combination of $C_2$ and $C_3$ is $C^{\text{'}}=\frac{C_2{C}_3}{C_2+C_3}=\frac{C}{2} \left(\because C_2=C_3=C\right)$
The common potential of $C_1$ and $C^{\text{'}}$ is
$V^{\text{'}}=\frac{Q_1}{C_1+C^{\text{'}}}=\frac{C_{1}V}{C_1+C^{\text{'}}}$
$=\frac{CV}{C+C/2}=\frac{2V}{3}$

$\therefore$ Final charge on $C_1$ is
$Q_1^{\text{'}}=C_1{V}^{\text{'}}=\frac{2CV}{3}$
$\therefore$ Charge that will flow through the connecting wires is

$Q^{\text{'}\text{'}}=Q_1-Q_1^{\text{'}}=CV-\frac{2CV}{3}=\frac{CV}{3}$,