Q.

A capacitor of capacitance C1=1μF  charged up to a voltage  V=110V is connected in parallel to the terminals of a circuit consisting of two uncharged capacitors connected in series and possessing the C2=2.0μFandC3=3.0μF capacitance . What charge will flow through the connecting wires in μC .

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answer is 60.

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Detailed Solution

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C23=2×32+3=1.2μF

qtotal=C1V=110μC

Common potential in parallel is given by

V=Total chargeTotal capacity

=1101+1.2=50V

q23=(C23)V=60μC

So, this much charge flows through the switch.

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