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Q.

A capacitor of capacitance 100 μF and a coil of resistance 50Ω  and  inductance 0.5H are connected in series with a 110 V, 50 Hz AC source. Find the rms value of the current.

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a

0.53 A

b

0.82 A

c

0.12 A

d

0.22 A

answer is B.

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Detailed Solution

Irms=VrmsZ=VrmsR2+ωL−1ωC2=110(50)2+2π×50×0.5−12π×50×100×10−62=0.82A

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