A capillary is dipped in water vessel kept in a freely falling lift, then

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Water will rise to the height below that observed under normal condition

Water will rise to the height observed under normal condition

Water will rise to the maximum available height of the tube

Water will not rise into the tube

answer is B.

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Detailed Solution

As we know,
height in a capillary tube is given by

$h = \frac{2 Tcos θ}{ρ g} \sin c e i n f r e e f a l l g = 0 h = \infty,$

hence
water will rise to the maximum available height of the tube and then start free falling.

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