A capillary tube has a uniform bore of radius 1 mm.  It is placed in water of surface tension 0.07 Nm^-1.  Mass of water raised into the capillary tube is

Weight of the liquid column is balanced by force due to surface tension

mg = $2\mathrm{\pi r}.\mathrm{Tcos\alpha }$

         r = 1 mm = 1 x 10^-3 

         T = 0.07

$\therefore \text{}\mathrm{m}=\frac{2\times \frac{22}{7}\times 1\times {10}^{-3}\times 7\times {10}^{-2}}{10}$

= 44 x 10^-6 kg=44 mg