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Q.

A capillary tube is immersed vertically into water in a vessel kept in a stationary lift, the rise of water in it is h. If the lift moves upwards with an acceleration 'a' then the rise of water in the capillary tube is

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a

$\frac{hg}{a - g}$

b

$\frac{hg}{a}$

c

$\frac{hg}{a + g}$

d

$h$

answer is C.

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Detailed Solution

The acceleration due to gravity is g,

The rise of water at a height of h

Thus the rise of water in the capillary tube is,

$h = \frac{2 S}{Rρcosθ}$

$h' = \frac{2 S}{Rρ (g + h) cosθ} = \frac{gh}{g + a}$

Hence the correct answer is $\frac{gh}{g + a} .$

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A capillary tube is immersed vertically into water in a vessel kept in a stationary lift, the rise of water in it is h. If the lift moves upwards with an acceleration 'a' then the rise of water in the capillary tube is