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Q.

A capillary tube of radius 0.25 mm is dipped vertically in a liquid of density 800 kg m-3 and of surface tension 3x 10-2 Nm-1.The angle of contact of liquid-glass is given by cosθ = 0.3. If g = 10ms-2 the rise of liquid in the capillary tube is ___ cm.

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a

9

b

0.9

c

9 × 10-3

d

0.09

answer is B.

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Detailed Solution

dgh=2Tcosθ ⇒h = 2Tcosθrdg ⇒h = 2×3 × 10-2×0.30.25 × 10-3 ×800 × 10  ⇒h = 0.9 cm

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