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A capillary tube of radius 0.25mm is submerged vertically in water so that 25mm of its length is outside water. The radius of curvature. of the meniscus will be $(T = 75 \times 10^{- 3} N / m)$

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0.4 mm

0.6 mm

0.8 mm

0.2 mm

answer is C.

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Detailed Solution

Given,

$Radius = 0.25 mm$

$surface tension = 75 \times 10^{- 3} N / m$

$height h = 25 mm$

We know that,

$h = \frac{2 T}{ρRg}$

$R = \frac{2 T}{ρRg}$

$R = \frac{2 \times 75 \times 10^{- 3}}{1000 \times 25 \times 10^{- 3} \times 10} = 0.6 mm$

Hence the correct answer is 0.6mm.

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