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Q.

A capillary tube of radius $r$ can support a liquid of weight $6.28 \times 10^{- 4} N$ . If the surface tension of the liquid is $5 \times 10^{- 2} N / m$ . The radius of capillary must be :-

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a

$2 \times 10^{- 3} m$

b

$2 \times 10^{- 4} m$

c

$1.5 \times 10^{3}$

d

$12.5 \times 10^{- 4} m$

answer is A.

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Detailed Solution

$m g = (2 π r) T \cos θ 6.28 \times 10^{- 4} = 2 π (r) \times (5 \times 10^{- 2}) \times 1 r = 2 \times 10^{- 3} m$

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A capillary tube of radius r can support a liquid of weight 6.28×10-4N . If the surface tension of the liquid is 5×10-2 N/m . The radius of capillary must be :-