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Q.

A capillary tube of radius r can support liquid of weight 6.28 x 10^-4N. If the surface tension of the liquid is 5 x 10^-2 N/m, the radius of the capillary must be:

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a

$1.5 x 10^{- 3} m$

b

$2.0 x 10^{- 4} m$

c

$2.0 x 10^{- 3} m$

d

$2.5 x 10^{- 4} m$

answer is D.

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Detailed Solution

$2 πrT = W \Rightarrow r = \frac{W}{2 πT} = \frac{6.28 \times 10^{- 4}}{2 \times 3.14 \times 5 \times 10^{- 2}} = 2 \times 10^{- 3} m$

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