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Q.

A car moving with a velocity of 54 kmph stops its engine just at the foot of a hill. If the car ascends a height of 10m, the energy lost in over coming friction is (g=10m/s2)

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An Intiative by Sri Chaitanya

a

30%

b

11.1%

c

20%

d

15%

answer is C.

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Detailed Solution

KE=12m(15)2    PE=mg×10

  %change KE−PEKE×100=12m(15)2−m×10012m(15)2×100

=225−200225×100

=252259×100=11.1%

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