Q.

A car ‘A’ moves due north at a speed of 40 km/hr, while another car ‘B’ moves due east at a speed of 30 km/hr. Find the velocity of car B relative to car A (both in magnitude and direction).

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a

40 km/hr, at an angle tan-1(35) east of south

b

50 km/hr, at an angle tan-1(35) east of south

c

40 km/hr, at an angle tan-1(34) east of south

d

50 km/hr, at angle tan-1(34) east of south

answer is D.

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Detailed Solution

vA  = 40 j^, vB  = 30i^

vB/A = vB -vA = 30i^-40j^

|vB/A| = 302+402 = 50 km/h

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