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Q.

A car accelerates from rest at a constant rate α for some time, after which it decelerates at constant rate  β and comes to rest. If the total time elapsed is t, then the maximum velocity acquired by the car is

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a

(α2+β2αβ)t

b

(α2−β2αβ)t

c

(α+β)tαβ

d

αβtα+β

answer is C.

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Detailed Solution

α=vt1⇒ t1=vα, β=vt2⇒ t2=vβ

t=t1+t2   =vα+vβ

v=αβtα+β 

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