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Q.

A car accelerates from rest at a constant rate of  2m/s2 for some time. Then it retards at constant rate of  4m/s2 and comes to rest. It remains in motion for 6s. 

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a

 Its maximum speed is 8m/s

b

Its maximum speed is 6 m/s

c

 It travels a total distance of 24m

d

It travels a total distance of 18m

answer is A, C.

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Detailed Solution

a1=2m/s2; a2=−4m/s2

v0=a1t1=2t1

v0=a2t2=4t2

t1t2=6

v02+v04=6

∴v0=8m/s

Total distance travelled

S=12V0t1+12V0t2

=12V0(t1+t2)

=12×8×6

24m

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