Q.

A car acquires a velocity of 72kmph in 10 s after starting from rest. The correct options 

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a

Distance travelled in this time is 100 m

b

Acceleration is 2 ms-2

c

Average velocity is 10 ms-1

d

Initial velocity is 5 ms-1

answer is A, B, C.

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Detailed Solution

Given that u = 0

(i) v=72 km/hr=72×518=20m/s t=10s,v=0 We can have a=v-ut a=2010=2m/s2 (ii) Average velocity =u+v2=0+202=10m/s (iii) Distance travelled s=ut+12at2 s=12×2×100=100m

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