A car acquires a velocity of 72kmph in 10 s after starting from rest. The correct options 

Given that u = 0

$$\begin{gathered} \left(i\right) v=72 km/hr=72\times \frac{5}{18}=20m/s \\ t=10s,v=0 \\ We can have a=\frac{v-u}{t} \\ a=\frac{20}{10}=2m/s^2 \\ \left(ii\right) Average velocity =\frac{u+v}{2}=\frac{0+20}{2}=10m/s \\ \left(iii\right) Dis\tan ce travelled s=ut+\frac{1}{2}a{t}^2 \\ s=\frac{1}{2}\times 2\times 100=100m \end{gathered}$$