A car and a bus are moving with the same Kinetic Energy. They are brought to rest by applying brakes which provide equal retarding forces. The distances covered by them before coming to rest will be

here a bus and car are said to be having same K.E i.e., K

And are brought to rest by applying same

Retarding force F, let ${\text{d}}_{\text{c}}{\text{,d}}_{\text{b}}$ are distances that car, bus travelled before

coming to rest

We know the work done $=\text{F}\times \text{S}$= change in K.E

$\text{F}\times {\text{d}}_{\text{car}}=\text{F}\times {\text{d}}_{\text{bus}}=\text{K}-0$

$\therefore {\text{d}}_{\text{car}}={\text{d}}_{\text{bus}}$

So option (c) is correct conclusion.

Apart from conclusions given in other options a, b, d.