A car between Mumbai and Hyderabad passed the 100-km, 160-km and 220-km points at 10.30 A.M., 11.30 A.M. and 1.30 P.M. Find the average speed of the car during the intervals 10.30 A.M. to 1.30 P.M.

The distance covered between 10.30 A.M. and 1.30 P. M. is 220 km – 100 km=120 km.

The time interval is 3 hours.

The average speed during this interval is $=\frac{\text{ Total Distance }}{\text{ Total Time }}$

Avg. Speed $=\frac{120}{3}=40 \mathrm{km}/\mathrm{hr}$