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A car falls off a ledge and drops to the ground in $0.5 \sec$ .

Let $g = 10 m / s^{2}$ , then find the height?

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1.25 m

12.5 m

125 m

0.125 m

answer is A.

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Detailed Solution

A car falls off a ledge and drops to the ground in

0.5 \sec

then the height is

1.25 m

Given time

= 0.5 \sec

g = 10 m / s^{2}

initial velocity will be zero due to free fall so,

u = 0

We know that

h = ut + \frac{1}{2} g t^{2}

,where

h

represents height

= 0 + \frac{1}{2} \times 10 \times 0.5 \times 0.5

= 1.25 m

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