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Q.

A car goes on a horizontal circular road of radius R, the speed is increasing at a constant rate ‘a’. If the friction coefficient between the road and tyre is $μ$ the speed at which the car will skid is

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a

${[(μ^{2} g^{2} + a^{2}) R^{2}]}^{1 / 2}$

b

$\sqrt{μ g R}$

c

${[(μ^{2} g^{2} - a^{2}) R^{2}]}^{1 / 2}$

d

${[(μ^{2} g^{2} - a^{2}) R^{2}]}^{1 / 4}$

answer is D.

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Detailed Solution

$μ m g = m \sqrt{a_{c}^{2} + a_{t}^{2}}$

$μ g = \sqrt{\frac{V^{4}}{R^{2}} + a^{2}}$

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