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A car has a driving mirror with a focal length of 40 cm. Another car of the same dimensions is 12 m away from the mirror of the first car. The position of the second car as seen in the mirror of the first car is:

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36 cm

49 cm

39 cm

44 cm

answer is C.

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Detailed Solution

f = 40 cm

$u = - 12cm$

$= - 1200 cm$

$\frac{1}{f} = \frac{1}{u} + \frac{1}{v}$

$\frac{1}{40} = \frac{- 1}{1200} + \frac{1}{v}$

$\frac{1}{v} = \frac{31}{1200}$

$v = 39cm$

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