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A car initially at rest starts moving with an acceleration of ${4ms}^{- 2}$ .The time in which it picks up a velocity of ${72ms}^{- 1}$ is

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$16s$

$18s$

$20 s$

$15s$

answer is B.

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Detailed Solution

$u = 0 m / s a = 4m / s^{2} V = 72m / s$

$a = \frac{V - u}{t} \to t = \frac{V - u}{a}$

$t = \frac{72 - 0}{4} = \frac{72^{18}}{4_{1}} s$

$t = 18 s$

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