A car is accelerated on a leveled road and attains a velocity 4 times of its initial velocity. In this process , the kinetic energy of the car is

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A car is accelerated on a leveled road and attains a velocity 4 times of its initial velocity. In this process , the kinetic energy of the car is

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Remains the same

Becomes 16 times to that of the initial

Becomes 4 times to that of the initial

Becomes twice to that of the initial

answer is D.

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Detailed Solution

K . E = \frac{1}{2} m v^{2}

= K

$K . E = \frac{1}{2} m {(14 v)}^{2}$

$= \frac{1}{2} m 16 v^{2}$

$= 16 \times \frac{1}{2} m v^{2}$

$= 16 K$

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