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Q.

A car is accelerating uniformly as it passes two check points that are 30 m apart. The time taken between check points is 4.0 s and the car’s speed at the first check point is  5.0ms−1. Then,

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a

the acceleration of car is  2.5ms−2

b

the velocity of car at second check point is  10ms−1

c

the acceleration of car is  2.25ms−2

d

the velocity of car at second check point is  20ms−1

answer is A.

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Detailed Solution

S=(U+V2)t

V=2St-U=604-5=10m/s

a=V−Ut

a=10-54=1.25m/s2

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