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A car is fitted with a convex side-view mirror of focal length 20 cm. A second car 2.8 m behind the first car is overtaking the first car at a relative speed of 15 ms^-1. The speed of the image of the second car as seen in the mirror of the first one is :

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$\frac{1}{10} {ms}^{- 1}$

$\frac{1}{15} {ms}^{- 1}$

10 ms^-1

15 ms^-1

answer is B.

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Detailed Solution

$\begin{array}{l} \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \\ O = \frac{1}{v^{2}} \cdot V_{I} - \frac{1}{u^{2}} \cdot v_{0} \\ V_{I} = - m^{2} \cdot V_{0} \end{array}$

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