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Q.

A car is moving along a straight horizontal road with a speed V0. If the coefficient of friction between the tyres and the road is μ, the shortest distance in which the car can be stopped is

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a

Vo22 μg

b

Voμg

c

(Voμg)2

d

Voμ

answer is A.

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Detailed Solution

Retarding force F=ma=μR=μ mg

∴  a=μg

Now from equation of motion υ2=u2−2as

⇒0=u2−2 as⇒s=u22a=u22 μg

 ∴  s=υo22 μg

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