A car is moving on a straight road due north with a uniform speed of 50 km h^-1 when it turns left through 90^o. If the speed remains unchanged after turning, the change in the velocity of the car in the turning process is

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$50 \sqrt{2} {kmh}^{- 1} S - W direction$

$50 \sqrt{2} {kmh}^{- 1} N - W direction$

$50 {kmh}^{- 1} due west$

answer is B.

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Detailed Solution

$\begin{array}{l} {\vec{v}}_{i} = 50 \hat{j} \Rightarrow {\vec{v}}_{f} = - 50 \hat{i} \\ Δ \vec{v} = {\vec{v}}_{f} - {\vec{v}}_{i} = - 50 \hat{i} - 50 \hat{j} \\ | \vec{Δ v} | = 50 \sqrt{2} km / h, SW \end{array}$

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