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A car is moving with a constant speed of 20 m/s in a circular horizontal track of radius 40 m. A bob is suspended from the roof of the car by a massless string. The angle made by the string with the vertical will be : (Take $g = 10 m / s^{2}$ )

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π/2

π/4

π/3

π/6

answer is C.

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Detailed Solution

$tanθ = \frac{v^{2}}{rg} = \frac{{(20)}^{2}}{40 \times 10} = 1$

$θ = 45 ° = \frac{π}{4}$

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