A car is moving with a speed of 30 m/s on a circular path of radius 500m. Its speed is increasing at the rate of 2m/s². The acceleration of the car is

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1.8m/s²

2.7m/s²

2m/s²

9.8m/s²

answer is D.

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Detailed Solution

$\begin{array}{l} a = \sqrt{a_{T}^{2} + a_{V}^{2}} \\ = \sqrt{2^{2} + {(\frac{900}{500})}^{2}} \\ = \sqrt{4 + \frac{81}{25}} \\ = \sqrt{\frac{181}{25}} \\ = \sqrt{7 .29} \\ = 2 .7 m / s^{2} \end{array}$

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