A car is moving with a speed of 30ms^-1 on a circular path of constant radius 500m. If its speed is increasing at the rate of 2 ms^-2, the net acceleration of the car is __________ms^-2

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answer is 2.7.

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Detailed Solution

$V = 30 m / s$

$r = 500 m a_{t} = 2 m / s^{2}$

$a_{net} = \sqrt{{(a_{c})}^{2} + {(a_{t^{}})}^{2}}$

$a_{net} = \sqrt{{(\frac{v^{2}}{r})}^{2} + (2)^{2}} \Rightarrow a_{net} = \sqrt{{(\frac{9}{5})}^{2} + (2)^{2}} \Rightarrow a_{net} = 2 .7 m / S^{2}$

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