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A car is moving with initial velocity 30 m/s. Car stopped after 10 sec by application of breaks. The retardation is …

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3 m/s²

-4 m/s²

-3 m/s²

-2 m/s²

answer is A.

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Detailed Solution

Acceleration $= \frac{Final velocity - Initial velocity}{Time}$

$\begin{array}{l} = \frac{0 - 30}{10} = - 3 {ms}^{- 2} \\ ∴ Retardation = - 3 {ms}^{- 2} \end{array}$

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