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A car is moving with velocity u. If car stop after applying break at a distance of 20 m. If velocity of car is doubled, then how much distance it wilt cover (travel) after applying break :

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80 m

40 m

160 m

320 m

answer is B.

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Detailed Solution

$v^{2} = u^{2} + 2 as \Rightarrow {(0)}^{2} = u^{2} + 2 (- a) s \Rightarrow s \propto u^{2} \Rightarrow \frac{20}{s'} = \frac{u^{2}}{{(2 u)}^{2}} \Rightarrow s' = 20 \times 4 = 80 m$

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