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Q.

A car is travelling at 36 kmph on a road. If $μ = 0.5$ between the tyres and the road, the minimum turning radius of the car is (g=10ms^–2)

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a

25 m

b

35 m

c

30 m

d

20 m

answer is A.

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Detailed Solution

The centripetal force is static friction.

$μmg = \frac{{mv}^{2}}{r} \Rightarrow r = \frac{v^{2}}{μg} = \frac{10^{2}}{(0.5) 10} = 20 m$

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