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A car moves up a hill of incline 1 in 50 with a velocity of 15KMPH. The resistance due to friction is 1/25 th of weight of the car. The speed of the car while moving down hill using same power is

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15KMPH

30KMPH

45KMPH

60KMPH

answer is C.

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Detailed Solution

$P = (\frac{m g}{50} + \frac{m g}{25}) v = (\frac{3 m g}{50}) \times 15 w h e n m o v i n g d o w n P' = (\frac{m g}{25} - \frac{m g}{50}) v = (\frac{m g}{50}) v b u t P = P' (\frac{45 m g}{50}) = (\frac{m g}{50}) v v = 45 k m p h$

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