A car moves up a hill of incline 1 in 50 with a velocity of 15 KMPH. The resistance due to friction is 125 th of weight of the car. The speed of the car while moving down hill using same power is

P=mg50+mg25v⇒P=3mg50×15when move down P1=mg25−mg50vP1=mg50v⇒P=P1⇒45mg50=mg50vv=45 KMPH

A car moves up a hill of incline 1 in 50 with a velocity of 15 KMPH. The resistance due to friction is 125 th of weight of the car. The speed of the car while moving down hill using same power is

P=mg50+mg25v⇒P=3mg50×15when move down P1=mg25−mg50vP1=mg50v⇒P=P1⇒45mg50=mg50vv=45 KMPH

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A car moves up a hill of incline 1 in 50 with a velocity of 15 KMPH. The resistance due to friction is $\frac{1}{25}$ th of weight of the car. The speed of the car while moving down hill using same power is

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30 KMPH

60 KMPH

15 KMPH

45 KMPH

answer is C.

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Detailed Solution

$P = (\frac{m g}{50} + \frac{m g}{25}) v \Rightarrow P = (\frac{3 m g}{50}) \times 15$
when move down $P^{1} = (\frac{m g}{25} - \frac{m g}{50}) v$
$P^{1} = (\frac{m g}{50}) v \Rightarrow P = P^{1} \Rightarrow \frac{45 m g}{50} = (\frac{m g}{50}) v$

v=45 KMPH

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A car moves up a hill of incline 1 in 50 with a velocity of 15 KMPH. The resistance due to friction is 125 th of weight of the car. The speed of the car while moving down hill using same power is

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A car moves up a hill of incline 1 in 50 with a velocity of 15 KMPH. The resistance due to friction is $\frac{1}{25}$ th of weight of the car. The speed of the car while moving down hill using same power is