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A car moving at speed ‘u’ applied brakes with constant retardation. If the speed of the car reduces to u/2 in thirty m, then total distance travelled by the car before coming to rest is

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30 m

40 m

60 m

10 m

answer is C.

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Detailed Solution

$\frac{1}{2} m (\frac{u^{2}}{4} - u^{2}) = 30 f$

$\frac{1}{2} m (0 - \frac{u^{2}}{4}) = f s$

$\Rightarrow \frac{3}{1} = \frac{30}{s} \Rightarrow s = 10 m$

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