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Q.

A car moving with a speed of $20 {ms}^{- 1}$ can be stopped by applying brakes, after travelling a distance of 2 m. The retardation of the car is

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a

50 {ms}^{- 2}

b

200 {ms}^{- 2}

c

150 {ms}^{- 2}

d

100 {ms}^{- 2}

answer is B.

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Detailed Solution

Initial velocity

u = 20 m/s

, Final velocity

v = 0m/s

, Distance travelled s = 2m, a = ?

We know $v^{2} - u^{2} = 2 as$

$a = \frac{v^{2} - u^{2}}{2 s} = \frac{0 - 400}{2 \times 2} = - 100 {m/s}^{2}$

$∴$ Retardation $(- a) = 100 {m/s}^{2}$

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A car moving with a speed of20 ms−1 can be stopped by applying brakes, after travelling a distance of 2 m. The retardation of the car is