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Q.

A car moving with a velocity of $10 {ms}^{- 1}$ and with a uniform acceleration gains a velocity of $30 {ms}^{- 1}$ after travelling a distance of 4 km. The time taken is

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a

400 s

b

100 s

c

300 s

d

200 s

answer is A.

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Detailed Solution

Initial velocity

u = 10 {ms}^{- 1}

, Final velocity

v = 3 {0ms}^{- 1}

Distance travelled $s = 4 km = 4 \times 10^{3} m$

$\Rightarrow s = (\frac{u + v}{2}) ×t = 4 \times 10^{3} = (\frac{10 + 30}{2}) . t$

$\Rightarrow t = \frac{4 \times 1000}{20} = 200 s$

$t = 200 s$

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