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Q.

A car moving with a velocity of10 ms−1  and with a uniform acceleration gains a velocity of 30 ms−1 after travelling a distance of 4 km. The time taken is

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a

400 s

b

100 s

c

300 s

d

200 s

answer is A.

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Detailed Solution

Initial velocityu=10ms−1 , Final velocity v=30ms−1

Distance travelled s=4km=4×103m

⇒s=(u+v2)×t=4×103=(10+302).t

⇒t=4×100020=200s

t=200s

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