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Q.

A car of mass 1000kg negotiates a banked curve of radius 90m on a frictionless road. If the banking angle is $45^{o}$ , then the speed of the car is [Here ${g = 10 m/s}^{2}$ ]

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a

5m/s

b

10m/s

c

20m/s

d

30m/s

answer is D.

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Detailed Solution

$tan θ = \frac{ν^{2}}{r g} \Rightarrow \tan 45^{o} = \frac{ν^{2}}{90 \times 10}$

$ν = 30m/s.$

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A car of mass 1000kg negotiates a banked curve of radius 90m on a frictionless road. If the banking angle is 45o , then the speed of the car is [Here g = 10 m/s2 ]