A car of mass 1250 kg experiences a resistance of 750N when it moves at 30ms^–1. If the engine can develop 30 KW at this speed, the maximum
acceleration that the engine can produce is

Given,

mass of car = m = 1250kg

Resistance = $F_R=750N$

speed = v = 30m/s

Power developed by engine =P = 30KW

Let the force developed by the engine by F

$$\begin{gathered} P = F.v \\ \Rightarrow 30\times {10}^3=30F \\ \Rightarrow F={10}^{3}N \end{gathered}$$

The net force on the car,

$={10}^3-750=250N$

$a=\frac{F}{m}=\frac{250}{1250}=0.2m/s^2$

Hence the correct answer is $0.2m/s^2.$