A car of mass 1400 kg placed on the platform in a service station has to be lifted. The area of the press piston to which the platform is fixed is 5 m2. Determine the force that has to be applied on the piston of the pump cylinder having an area of cross-section 0.25 m2. (Take g = 10 m s–2)

Given, the mass of the car, m = 1400 kg∴ Weight of the car = force on the press piston = mg = 1400 × 10 = 14000 N.Area of the press piston, A2 = 5 m2Area of the pump piston, A1 = 0⋅25 m2Let the force to be applied on the pump piston be ‘F1’∴F1 A1=F2 A2 ⇒F1=F2 A2×A1=140005×0·25 ⇒F1=700 N.

A car of mass 1400 kg placed on the platform in a service station has to be lifted. The area of the press piston to which the platform is fixed is 5 m2. Determine the force that has to be applied on the piston of the pump cylinder having an area of cross-section 0.25 m2. (Take g = 10 m s–2)

Given, the mass of the car, m = 1400 kg∴ Weight of the car = force on the press piston = mg = 1400 × 10 = 14000 N.Area of the press piston, A2 = 5 m2Area of the pump piston, A1 = 0⋅25 m2Let the force to be applied on the pump piston be ‘F1’∴F1 A1=F2 A2 ⇒F1=F2 A2×A1=140005×0·25 ⇒F1=700 N.

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A car of mass 1400 kg placed on the platform in a service station has to be lifted. The area of the press piston to which the platform is fixed is 5 m². Determine the force that has to be applied on the piston of the pump cylinder having an area of cross-section 0.25 m². (Take g = 10 m s^–2)

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175 N

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750 N

answer is D.

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Detailed Solution

Given, the mass of the car, m = 1400 kg

∴ Weight of the car = force on the press piston = mg = 1400 × 10 = 14000 N.

Area of the press piston, A₂ = 5 m²

Area of the pump piston, A₁ = 0⋅25 m²

Let the force to be applied on the pump piston be ‘F₁’

$∴ \frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}} \Rightarrow F_{1} = \frac{F_{2}}{A_{2}} \times A_{1} = \frac{14000}{5} \times 0 \cdot 25 \Rightarrow F_{1} = 700 N .$