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Q.

A car of mass 500 Kg turns on a banked frictionless road of radius $10 \sqrt{3}$ m. If banking angle is 30°, find speed of the car(g=10m/s²)

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a

30 m/s

b

20 m/s

c

5 m/s

d

10 m/s

answer is B.

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Detailed Solution

$\tan θ = \frac{v^{2}}{rg} \Rightarrow \tan 30^{\circ} = \frac{v^{2}}{10 \sqrt{3} \times 10}$
$v = 10 m / s$

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