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A car P travelling at $20 {ms}^{- 1}$ sounds its horn at a frequency of $400 Hz$ . Another car Q is travelling behind the first car in the same direction with a velocity $40 {ms}^{- 1}$ . The frequency heard by the passenger of the car Q is approximately [Take, velocity of sound $= 360 {ms}^{- 1}$ ]

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$421 Hz$

$471 Hz$

$485 Hz$

$514 Hz$

answer is A.

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Detailed Solution

According to doppler effect, the apparent frequency is given by

$n^{1} = [\frac{C + ϑ_{Q}}{C + ϑ_{P}}] n = \frac{400}{380} \times 400 = 421 Hz$

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