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A car passes along a curved path of a road according to figure moving with speed of 72 km h^-1, radius of curve is 10 m. If mass of the car is 500 kg, reaction force (in kN) on car at lowest point of curved part will be _______.

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Detailed Solution

$a_{c} = \frac{v^{2}}{r} = {(\frac{72 \times 1000}{3600})}^{2} \times \frac{1}{10} = 40 {ms}^{- 2}$

$F_{c} = {ma}_{c} = (500 \times 40) = 20000 N = 20 kN$

$F_{g} = mg = (500 \times 10) = 5000 N = 5 kN$

Reaction force, $F = 20 kN + 5 kN = 25 kN$

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