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A car starting from a point travels towards east with a velocity of 36 kmph. Another car starting from the same point travels towards north with a velocity of 24 kmph. The relative velocity of one with respect to another is

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30 kmph

12 kmph

20 kmph

12 $\sqrt{13}$ kmph

answer is A.

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Detailed Solution

$\vec{V_{12}} = \vec{V_{1}} - \vec{V_{2}} = 36 \hat{i} - 24 \hat{j} \Rightarrow |\vec{V_{12}}| = \sqrt{36^{2} + 24^{2}} = 12 \sqrt{13} kmph$

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