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A car starting from rest is accelerated at constant rate until it attains a constant speed v. It is then retarded at a constant rate until it comes to rest. Considering that the car moves with constant speed for half of the time of total journey, the average speed of the car for the journey is

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$\frac{v}{4}$

$\frac{3 v}{4}$

$\frac{3 v}{2}$

answer is B.

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Detailed Solution

$v_{avg} = \frac{\frac{1}{2} \times \frac{t}{2} \times v + \frac{1}{2} \times v}{t} = \frac{3 v}{4}$

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