A car starts from rest. It moves with uniform acceleration. In 10 second, it attains a speed of 12 km/h a straight road. Find its acceleration.

Kinematics equations of motion define the fundamentals of an object's motion, such as its position, velocity, or acceleration over time. These three equations of motion control how an item moves in one, two, and three dimensions. One of the most crucial subjects in Physics is how the equations of motion are derived. In this article, we'll demonstrate how to use the graphical, algebraic, and calculus methods to derive the first, second, and third equations of motion. v = u + at is the first equation of motion. Here, v denotes the end speed, u the starting speed, the acceleration, and t the passage of time. The first equation of motion is provided by the velocity-time relation, which may be used to calculate acceleration.

First we will write the given values that is
As the car starts from rest, therefore, the initial velocity $u$ equal to $0$$km/hr=$ $0$$m/s$
The final velocity $v$ equal to $12$ $km/hr=$${\displaystyle \frac{5\times 12}{18}}$$m/s$$={\displaystyle \frac{10}{3}}$ $m/s$
The timet $t$ equal to $10$ sec
Now we know the first equation of motion that is
$v=u+at$
$\Rightarrow {\displaystyle \frac{10}{3}}=0+a\times 10$

$\Rightarrow {\displaystyle \frac{10}{3}}=a\times 10$

$\Rightarrow a=\frac{1}{3}m/s^2$
 Hence, the option B is correct.