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A car weighing $1600 kg$ is accelerated to $30 m / s$ from start in $20 s$ . The magnitude of the force applied is

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1000 N

4800 N

2400 N

4000 N

answer is C.

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Detailed Solution

A car weighing

1600 kg

is accelerated to

30 m / s

from start in

20 s

. The magnitude of the force applied is

2400 N .

Given that,
Mass

(m) = 1600 kg

Initial velocity

(u) = 0 m / s

as its car started.
Final velocity

(v) = 30 m / s

Time

(t) = 20 \sec

Acceleration,

a = \frac{v - u}{t}

= > a = \frac{0 - 30}{20}

= > a = - 1.5 m / s^{2}

Acceleration,

a = - 1.5 m / s^{2}

From the second law of motion,

F = ma

= > F = 1600 \times (- 1.5)

= > F = - 2400 N

The negative sign here represents that the force is applied in a direction opposite to the motion of the car.

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