A carbon compound catains 4.07% hydrogen, 24.27 % carbon and 71.65% chlorine. Its nuclear mass is 98.96 gm. What are its empirical and molecular formulas?

$\therefore$Emperical formula = CH₂Cl
M.F = (E.F)_n
$\mathrm{n}=\frac{\text{ molecular weight }}{\text{ emperical formula weight }}$
Emperical formula weight CH₂Cl
$=12+2+35.5=49.5\Rightarrow \mathrm{n}=\frac{98.96}{49.5}=2$
Therefore, Molecular formula
(CH₂Cl)₂ = C₂H₄Cl₂