A card is drawn at random from a pack of cards. The probability that the card is either a face card (Jack, Queen, King) or a six is

$n\left(S\right)={52}_{C_1}=52$

Face cards = 4 jack +4 queen +4 king

$\therefore n\left(E\right)={12}_{C_1}=12$

$n\left(F\right)=4_{C_1}=4$

$P(E\cup F)=P\left(E\right)+P\left(F\right)$

                    $=\frac{12}{52}+\frac{4}{52}=\frac{4}{13}$

$\therefore$ The probability that the card is either a face card (Jack, Queen, King) or a six is $\frac{4}{13}$